0=-16.1x^2+20.57x+3

Solution for 0=-16.1x^2+20.57x+3 equation:

0=-16.1x^2+20.57x+3

We move all terms to the left:

0-(-16.1x^2+20.57x+3)=0

We add all the numbers together, and all the variables

-(-16.1x^2+20.57x+3)=0

We get rid of parentheses

16.1x^2-20.57x-3=0

a = 16.1; b = -20.57; c = -3;
Δ = b2-4ac
Δ = -20.572-4·16.1·(-3)
Δ = 616.3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20.57)-\sqrt{616.3249}}{2*16.1}=\frac{20.57-\sqrt{616.3249}}{32.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20.57)+\sqrt{616.3249}}{2*16.1}=\frac{20.57+\sqrt{616.3249}}{32.2}
$